Short cut methods in quantitative aptitude

Short cut methods in quantitative aptitude

Todays all competitive exams are having the topics of quantitative aptitude and reasoning.If you know the solving method for particular problem in seconds,then you can said to be good in aptitude.In aptitude for every problem or question we have short cut methods.

why aptitude

Why  and where to apply short cut methods

  • in bank exams like IBPS
  • Written test for MNC job

CAT,MAT,GRE,GATE ,railways exams,lic,all national level exams

formula or trick ?

we are not going to solve the problems in formula,hate formulas,try to solve in logical methods,which are not related to any formula.So we are giving you suggestion that,apply tricks,which improves your logical thinking and attitude

Where i  have to learn these tricks to solve  quantitative aptitude problems?

These methods/tricks  will not available in any books or any other websites,no any website providing the short cut tricks to solve the problems in less time.In this site you can learn aptitude short cut methods

IBPS EXAM SPECIAL

Learn short cut methods in aptitude to get your dream job,so for every day,apply new methods to solve the problems by using our short cut methods.Start from here,the lessons for aptitude tricks from all topics.Today we are explaining you,short cut methods in percentage topic ,which related to aptitude.

LESSON 1 -SHORT CUT METHODS/TRICKS IN PERCENTAGES

CONCEPT:

Important Points to Note:

  1. When any value increases by
    1. 10%, it becomes 1.1 times of itself. (since 100+10 = 110% = 1.1)
    2. 20%, it becomes 1.2 times of itself.
    3. 36%, it becomes 1.36 times of itself.
    4. 4%, it becomes 1.04 times of itself.

Thus we can see the effects on the values due to various percentage increases.

  1. When any value decreases by
    1. 10%, it becomes 0.9 times of itself. (Since 100-10 = 90% = 0.9)
    2. 20%, it becomes 0.8 times of itself
    3. 36%, it becomes 0.64 times of itself
    4. 4%, it becomes 0.96 times of itself.

Thus we can see the effects on a value due to various percentage decreases.

Note:

1. When a value is multiplied by a decimal more than 1 it will be increased and when multiplied by less than 1 it will be decreased.

2. The percentage increase or decrease depends on the decimal multiplied.

Eg: 0.7 => 30% decrease, 0.67 => 33% decrease, 0. 956 => 4.4% decrease and so on.

Eg: When the actual value is x, find the value when it is 30% decreased.

Soln: 30% decrease => 0.7 x.

Eg: A value after an increase of 20% became 600. What is the value?

Soln: 1.2x = 600 (since 20% increase)

ð     x = 500.

Eg: If 600 is decrease by 20%, what is the new value?

Soln: new value = 0.8 X 600 = 480. (Since 20% decrease)

Thus depending on the decimal we can decide the % change and vice versa.

Eg: When a value is increased by 20%, by what percent should it be reduced to get the actual value?

Soln: (It is equivalent to 1.2 reduced to 1 and we can use % decrease formula)

% decrease = (1.2 – 1)/1.2 X 100 = 16.66%.

  1. When a value is subjected multiple changes, the overall effect of all the changes can be obtained by multiplying all the individual factors of the changes.

Eg: The population of a town increased by 10%, 20% and then decreased by 30%. The new population is what % of the original?

Soln: The overall effect = 1.1 X 1.2 X 0.7   (Since 10%, 20% increase and 30% decrease)

= 0.924 = 92.4%.

Eg: Two successive discounts of 10% and 20% are equal to a single discount of ___

Soln: Discount is same as decrease of price.

So, decrease = 0.9 X 0.8 = 0.72 => 28% decrease (Since only 72% is remaining).

 

practice problems:

  1. If 20% of 40% of a = 25% of a% of b, then what is b?

a. 8/5               b. 16/25                       c. 8/25             d. None

2. By what % is 200 more than 50?

a. 100              b. 200                          c. 300              d. None

3. A value changes from 30 to 80. What is the percentage change?

a. 125              b. 166.66                     c. 156              d. None

4. The population of a city is increased by 30% and thus became 78000. What is the original population?

a. 76000          b. 64200                      c. 60000          d. None

5. In a theatre, the number of seats is increased by 20% and the price per ticket is increased by 10% but the public response decreased by 30%. What is the net effect on the economy of the theatre?

a.10% rise        b. 7% fall                      c. 7% rise         d. None

6. A saves 20% of his income. His income is increased by 20% and so he increased his expenditure by 30%. What is the percentage change in his savings?

a. 20% fall        b. 4% fall                      c. 20% rise       d. 4% rise

7. The price of petrol is increased by 25%. By what percent the consumption be reduced to make the expenditure remain the same?

a. 25%             b. 33.33%                    c. 20%             d. None

8. The side of a square is increased by 20%. The percentage change in its area is ___

a. 20%             b. 44%                         c. 36%             d. None

9. If the length of a rectangle is increased by 33.33%, by what percentage should the breadth be reduced to make the area same?

a. 20%             b. 33.33%                    c. 25%             d. None

10. In an election between two candidates, A and B, A secured 56% of the votes and won by 48000 votes. Find the total number of votes polled if 20% of the votes were declared invalid.

a. 500000        b. 400000                    c. 600000        d. None

clear explanation for  above problems:

  1. 1/5 X 2/5 X a = ¼ X a X b  =>  b = 8/25
  2. % difference = (200-50)/50 X 100 = 300 %
  3. % increase = (80-30)/30 X 100 = 166.66 %
  4. 1.3 x = 78000  =>  x = 60000.
  5. Net effect = 1.2 X 1.1 X 0.7

= 0.924  =>  7.6% decrease.

  1. Let I be the income.

Expenditure = 0.8I                 Savings = 0.2I => 20%

New income = 1.2I  (since 20% rise)

New expenditure = (0.8I) X 1.3  (Since 30% rise)

= 1.04I

So, new savings = 1.2I – 1.04I = 0.16I => 16%

(So income decreased form 20% to 16%)

% decrease = (20-16)/20 X 100 = 20%.

  1. It is equivalent to 1.25 decreased to 1.

% decrease = (1.25-1)/1.25 X 100 = 20%

8. % change in area = 1.2 X 1.2 (since area = side X side)

= 1.44 => 44%.

  1. It is equivalent to 1.25 decreased to 1. So 20% decrease.
  2.        Valid Votes:

A got 56%  =>  B got 44%

Difference = 12% = 48000

So, 100% = 400000. These are valid votes.

But valid votes are only 80% of total votes.

So, 80% of total votes  = 400000  =>  total votes = 500000

STILL CONFUSE?SUBMIT YOUE QUIRY IN LEAVE REPLY/SUBMIT COMMENT

 

 

 

 

 

 

Comments

  1. thanx
    ts a gr8 help

    • hey these are the very good logics but i am unable to capture the data in the question could you please help me out with this

  2. VERRY GOOD

  3. TOO COOL

  4. thanks

  5. Dear Sir,

    Could you please explain me 9th Question in details?

    Thanks in Advance

  6. how abt the short cuts for train sums,,

  7. It’s really good but i don’t understand 9 question?????

  8. gud one…….

  9. its super cool thnks

  10. Thanks and we will provide all short cut methods for free in the form of video tutorials,which will introduce shortly in this website

  11. HEY CAN PLZ…TELL ME SHORT CUTS OF LCM,HCM………….REPLY MUST AS SOON AS POSSIBLE

  12. u r providing beautiful tips in a very simpler manner thank u so much i have a small doubt
    1) in decrease of percentage we use higher no in denominator
    2)in increase of percentage we use smaller no
    plz clarify

    • yeah…
      just look it by the method of fractions…
      for increment just increase the whole value by using -1 no, in denominator.
      n for decrement use the other one like +1 to denominator.
      but for dat.. u first convert d percentage to the fractional form..

  13. Q.Sum of 5 consecutive odd numbers is 175.what is the second highest number.?
    Ans.175/5 = 35
    35 is mid value
    So 35 has two consecutives upper values 37 & 39 and two lower values are 33 & 31.
    Series is 31,33,35,37,39
    So the Ans is 37

  14. Q.Sum of 5 consecutive odd numbers is 175.what is the second highest number.?
    Ans.175/5 = 35
    35 is mid value
    So 35 has two consecutives upper values 37 & 39 and two lower values are 33 & 31.
    Series is 31,33,35,37,39
    So the Ans is 37

  15. ITS SO NICE.I REALLY THANKS TO GIVE TRICKS BUT PLEASE GIVE TRICKS FOR OTHER TOPICS.
    THANK YOU ONCE AGAIN

  16. i dont understand 10 ques.how 400000 will occured?

  17. I Have some problem in question no.10 If 20% votes are invalid so we should minus from 100 and then substract 56% then we will get 24%..and After that we get 20000 total votes.

  18. hi
    did u got any shortcuts on percentages..
    if so pls tel me

  19. i have doubt that is how to calculate 8% of 800*?=224
    4/7*2/3*?=1008
    5.5*6.4/0.4=?.

  20. Hey thanks so much. so helpful. but kindly help me out with Qs 9 and 10. thank you once again

  21. sir
    plz post shortcut methods for work related problems.

  22. Thanku. very nice.but i need some more logical reasoning test for pratice

  23. Thank you

    its simply awesome

    my exam is on 11 dec

    now i will clear tthis topic

  24. AMIT KANOJIA MA'DY :

    first of all i would ilke to thanks ….
    fr d the outstanding sortcut methods
    nw my concept of this chapter is clear.
    thanks a lot.

  25. i like the why to solve question but this is only one topic if somebody have anouther topic short cut so plz send me on my id rohit.singh088@gmail.com

  26. how to answer synonymsand antonyms by shortcut metbod?

  27. gud trick
    Thank u

  28. i realy confused……………..

  29. thanks…its useful ……but i m confused with 5 th answers solution

  30. it’s really fantastic one.but by explaining vth videos is normally a better choice

    • Very Valuable Suggestion,We also have planned to release videos on aptitude and reasoning short cuts and concepts.Hope will release soon
      Always video tutorials reach nicely

      • Is there short cuts available for solving problems cube roots and higher order roots , multiple ratios, to find the time taken for one person when days taken by combined people is given

  31. The answer for the first question is wrong or the question is wrong because in the first question it is a% at the right side if so the answer is 32 not 8/25.

  32. it was really good…….but,
    sir i have dought on 7,8,9,10 que and also help me in remaning topics…in feb iam gng to write gate so please suggest me some techniques about gate……..plzzzzzzzzzzzzz

  33. The percentage problem are very nice and usefull but still I have some confussion. If you give little more explanation means it will be ok for all…. I learned something…

  34. could you plz explain a 10th problem again

  35. suresh kumar challa :

    these short cut methods are really helpfull in solving problem in percentage ,thank you

  36. in first problem 20%=20/100=1/5, 40%=40/100=2/5, 25%=25/100=1/4 ok then a%=a/100 why u mention it as just a

  37. 2.8 x 25.3 + 18 ÷ 10.2 = ? How to solve this problem using tricks?

  38. this shortcuts are easy to solve 80% of questions on percentages…but i want shortcuts in other topics…plz is there any chance of sending this topics to my mail…plzz.,

  39. Grt work frnd pls help me with time based problems

  40. Thanks for the tricks

  41. it was very usefull .. and its easy to learn thanx….

  42. please explain Q.9.

  43. Aptitude is very important and I was really fed up with preparing this.
    Now I got a simple trick to do it
    thanks for the short cut!

  44. Pls send me some easy tricks i want help

  45. excellent….

  46. raghav kesar :

    ohhh it is just awesome.. website..

  47. in question 9 the answer should be 30% therefore None in the given options as the next decreased value from 33.33% is 30% as explained in ur another Topic.

  48. so much thanks

  49. so many thanks…….Osam site of many which i mostly come across

  50. Very useful

  51. yhank u a lot
    pls also help in solving reasongi probles
    my reasonig is toooooooooooooooooooooooooo bad
    i want io improv ethis

  52. Thanks 4r the shortcut…. Bt can it be possible to send more of the short cuts on other apptitue problems… If possible plz help7.77777

  53. i have not understood 9 th problem

  54. Rajan Shrivastava :

    thanks a lot it really helped me : best wishes from my side to this site be a gr8 success

  55. Simply super.. Hearty thanks for your helpful tricks to solve percentage. COuld you please send the short cuts to remaining concepts to my mail iD? OR intimate me when you released the videos for other concepts?

    I’m waiting here for your valuable reply.

  56. Thank you !
    Need such kinds of aid in Reasoning too. Are you updating this site regularly?

  57. lovely experience from that

  58. Question 9 answer is 25% i.e. c option……….. rest all is very useful….. thanx…..

  59. pls ,provide shortcuts for probability,time &distances,trains with in one day

  60. answer of the q 9 is 25%

    let the length =X & breadth = Y
    den area = XY

    new length= X*133.33/100

    but the area should be same den,let the breadth decresd by (100-Z)%, now

    X*133.33/100*Y(100-Z)/100 = XY
    100-Z = 100*100*100/13333 === 75%

    so Z = 25%

  61. its very useful short cuts.. kindly tell about vacbouray & analytical shortcuts also …. how to judge ?? m very weak in it :(

  62. thanx .a lot 4 giving some shortcut option

  63. sir thanks for building such a wonder website but if some more test papers are added then it would be much more interesting and useful in all respect

  64. Hi sir. Can u send the content short cut methods for all types of aptitude question.
    Solving techniques

  65. except 9 th ques all were good
    9th ans is 25
    (1.3333-1)/1.3333*100=24.99=25

  66. fantastic …..super like .

  67. plz help me in solving this problem
    One year ago beaties was 4 times as old as his son.in 6 years time his age exceeds twise his son’s age by 9 years . The ratio me their present ages is
    option 1. 9:2
    option 2. 11:3
    option 3. 12:5
    option 4. 13:4

  68. plz help me in solving this problem
    One year ago beaties was 4 times as old as his son.in 6 years time his age exceeds twise his son’s age by 9 years . The ratio me their present ages is
    option 1. 9:2
    option 2. 11:3
    option 3. 12:5
    option 4. 13:4

    • Hi harini hear is ur solution…
      Let the son age be a x and beaties be 4x at one year ago .
      After 6 years they will be x+6 , 4x+6.
      Given that beaties exceeds 9 years hence it will be
      (4x+6)+9 = x+6
      then x is 3.after one year it will be 4 and beaties will be 13
      hence their ratio is 13:4..
      For any quries contact me sforsuresh999@gmail.com

      • hi sir i knw am too late.
        sir can u xplain me
        One year ago beaties was 4 times as old as his son.in 6 years time his age exceeds twise his son’s age by 9 years . The ratio me their present ages is

  69. i dont have any idea abt apps round . but now i hope , when i atten % app questons , i secured good marks. its very useful for me. thaks .
    i need shortcuts in other topics…plz is there any chance of sending this topics to my mail…

  70. Hi sir. Can u send the content short cut methods for all types of aptitude questions.
    Solving techniques

  71. Hi sir. Can u send the content short cut methods for all types of aptitude question.
    Solving techniques

  72. hi…………nice tricks…….kindly help me 2 explore another type of question?

  73. pls send the logical tips for solving the problems

  74. Hi ,
    where are other lessons ? I could not find other than LESSON 1 -SHORT CUT METHODS/TRICKS IN PERCENTAGES

  75. Hey whats that stupid answer for 9th qustion… Elobarate it clearly

  76. Can you send me any shortcut formula for Time & Distance

  77. helpful for our compus test…thanks.

  78. thanks
    what about other shurt cuts
    is it end with percentage ?
    please give other questions shurt cuts

  79. good work

  80. its really to read the concept
    thank u…..

  81. the solution given for question.9 is wrong…
    the ans. should b 25 not 20…
    cz if one thin is increased by 33.33 % (1/3 in fraction) den the other one should decrease by 25% (1/(3+1) = 1/4 in fractions) .. n vice versa..

  82. thank you,really useful for students

  83. my question is -
    Due to a 25% increase in the price of rice per kg, a person is able to purchase 20kg less for rupees 400. What is the increased price of rice
    per kg?

  84. give me some other shortcut on another topic…………

  85. nice

  86. sir time & work shortcut methods formula please give me

  87. I know all these, please post something new Sir

  88. viswa schoolof banking :

    GREAT WORK SIR
    WE TAKE CLASS FOR BANK EXAMS TNPSC RAILWAYS SSC IN OTHER EXAMS WITH SHORT CUT METHOD USE TO TEACH.
    BY
    VISWA SCHOOL OF BANKING OPP OF AIRTEL
    11 TH CROSS THILLAI NAGER TRICHY-18
    7402587727,8220631395

  89. Plz explain those probes are clearly

  90. hey i want shotcut tricks for profit and loss… anyone can help me… pls…

  91. really nice and easyyy ……………….thax alooottt

  92. this is very helpful.. im trying to find the right place to do my master,

  93. give me the tricks for po clerk exams question i want to give the exams of banks.

  94. sir ans of q1 is wrong because on right hand side its %a not only a

  95. shanmugaraja :

    answer for question 9 is 25%

  96. Debasis pradhan :

    Sir,
    how to solve 3333*333*33*3 using short tricks.pls inform me

  97. can u send me the tricks for other topics…its really a worthy one.

  98. Really useful tips..!!!
    Thank u sir..!!

  99. pls send qantitude aptitudu tricks

  100. thanks for your tips but for next lesson

  101. hi , please tell shortcut method to solve question of type2345+567-879{20%456}-568.
    i am preparing for rbi grade b exam n dont know how to solve such question quickly.

  102. sir am weak in aptitude prob.s please could u help me how to solve those prob.s in easy way, is der any chance to send the tricks to my mail id: deepika.bhanu11@gmail.com

  103. Where the answer key is available? i have to check my answers for the problems are right. And also i am confused with 5 th question can anyone explain.

  104. still confusion

  105. it is really helpful

  106. thanks for methods

  107. 9,10 qustion dought

  108. Great post about aptitude shortcuts tips. It’s very useful. Thanks for sharing.

  109. Aptitude shortcuts is very useful for the preparation. Thanks for sharing

  110. really it was helpfull……. plz help us to learn other topics wit shortcuts

  111. Sreenivas Prathap :

    Sir can you plz send the maths trics(all topics like speed,time,calender,ages etc.) to my mail id.
    plz plz send me

  112. I did not understand the solution of 9 question

  113. vry use ful

  114. suryawansh kumar :

    solution of ques no.1 is wrong it should be like this, 1/5 X 2/5 X a = ¼ X (a/100) X b => b =32

  115. So informative and great to learn,,

    Thank you so much!!!

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