Letter series and types of letter series

LETTER SERIES

Type – 1:

  • A series of single, pairs of groups or combination of letters and numerals is given.
  • The terms of the series form a certain pattern as regards the position of the letters in the English alphabet.
  • You have to decipher the pattern and accordingly, find the missing term or wrong term in the given series.

Examples:

  1. A, C, F, J, ?, ?

Sol: A (B) C, C (D, E) F, F (G, H, I) J, J (K, L, M, N) O, O (P, Q, R, S, T) U

So, the next terms are O, U.

  1. AC, FH, KM, PR, ?

Sol: See all the first letters of the given series.

A (B, C, D, E) F, F (G, H, I, J) K, K (L, M, N, O) P (Q, R, S, T) U

Now, see all the second letters of the given series.

C (D, E, F, G) H, H (I, J, K, L) M, M (N, O, P, Q) R (S, T, U, V) W

So, the next term will be UW.

  1. BMO, EOQ, HQS, ?

Sol: See all the first letters of the given series.

B (C, D) E, E (F, G) H, H (I, J) K

Now, see all the second letters of the given series.

M (N) O, O (P) Q, Q (R) S

Now, see all the third letters of the given series.

O (P) Q, Q (R) S, S (T) U

So, the next term will be KSU.

  1. ?, WFD, UHG, SKI, QOL

Sol: See all the first letters of the given series from last term.

Q (R) S, S (T) U, U (V) W, W (X) Y,

Now, see all the second letters of the given series from first term.

E (-) F, F (G) H, H (I, J) K, K(L, M, N) O

Now, see all the third letters of the given series.

B (C) D, D (E, F) G, G (H) I, I (J, K) L

So, the missing term will be YEB.

Type – 2:

Alpha-Numeric Series: It is a jumbled combination of Alphabetic and Numeric series.

Examples:

  1. Z1A, X2D, V6G, T21J, R88M, ?

Sol: The series formed by the numerals 1, 2, 6, 21, 88,… follow the pattern

x 1 + 1, x 2 + 2, x 3 + 3, x 4 + 4, …

So, numeral in the desired term = 88 x 5 + 5 = 445

Observe the first letters of all the terms.

Z (Y) X, X (W) V, V (U) T, T (S) R, R (Q) P

Observe the second letters of all the terms.

A (B, C) D, D (E, F) G, G (H, I) J, J (K, L) M, M (N, O) P

So, the next term in the series will be P445P.

  1. Find the odd man out from the following series.

G4T, J10R, M20P, P43N

Sol: Observe the pattern followed by the first letter in all the terms.

G (H, I) J, J (K, L) M, M (N, O) P

Observe the pattern followed by the second letter in all the terms.

T (S) R, R (Q) P, P (O) N

Observe the pattern followed by the numerals in all the terms.

Here, if x 2 + 1 rule is satisfied then second term should be J9R.

This rule can be applied to whole series except the second term.

So, J10R is the odd man.

Type – 3:

Continuous Pattern Series:

  • This type of series usually consists of a small letters which follow a certain pattern.
  • But some letters will be missing from the series.
  • These missing letters are then given in a proper sequence as one of the choices.
  • You have to choose the correct alternative.

Example:

  1. aab _ aaa _ bba _

1) baa                                      2) abb

3) bab                             4) aab                             5) bbb

Sol:

Step 1: Fill the first blank space by ‘b’ so that you can have two a’s followed by two b’s.

Step 2: Fill the second blank space either by ‘a’ so that you have four a’s followed by two b’s or ‘b’ so that you have three a’s followed by three b’s.

Step 3: The last space must be filled by ‘a’.

Step 4: So, now you can have two possible answers: ‘baa’ and ‘bba’. But, only baa appears in the choices. Thus 1 is the answer.

Step 5: In case, you have both the possible answers in the choices, you have to chose the one that forms a more prominent pattern, which is aabb/aaabbb/aa. Thus, your answer should be ‘bba’.

Comments

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  2. Please help me solve this letter series, r,u,x,a,d,? And z,x,s,I,r,r,?,?

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